Fill every row and every column with the digits 1 to 7, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 7 addition cages, 6 subtraction cages and 5 multiplication cages.
5 cells are printed for you: a 1 at row 1, column 3; a 5 at row 4, column 4; a 1 at row 5, column 7; a 3 at row 6, column 3; and a 2 at row 7, column 1. Fill those in first, then let each one rule its digit out of its row and column.
3 cages allow a single combination of digits — the safest openings this grid offers: the 140× cage at row 3, column 3 (4 × 5 × 7); the 100× cage at row 6, column 7 (4 × 5 × 5); the 35× cage at row 1, column 1 (5 × 7).
Cage by cage
What each cage’s arithmetic allows on its own, before the rows and columns have a say — the most constrained first, which is the order worth looking at them in. Digits may repeat inside a cage only where the cells share no row or column.
The 140× cage at row 3, column 3 (3 cells) can only be 4 × 5 × 7.
The 100× cage at row 6, column 7 (3 cells) can only be 4 × 5 × 5.
The 35× cage at row 1, column 1 (2 cells) can only be 5 × 7.
The 72× cage at row 1, column 5 (3 cells) could be 2 × 6 × 6 or 3 × 4 × 6 — the grid leaves only 3 × 4 × 6.
The 5+ cage at row 2, column 1 (2 cells) could be 1 + 4 or 2 + 3 — the grid leaves only 1 + 4.
The 5− cage at row 3, column 2 (2 cells) could be 6 − 1 or 7 − 2 — the grid leaves only 7 − 2.
The 5− cage at row 7, column 2 (2 cells) could be 6 − 1 or 7 − 2 — the grid leaves only 6 − 1.
The 24× cage at row 3, column 6 (3 cells) could be 1 × 4 × 6, 2 × 2 × 6 or 2 × 3 × 4 — the grid leaves only 2 × 3 × 4.
The 9+ cage at row 5, column 1 (2 cells) could be 2 + 7, 3 + 6 or 4 + 5 — the grid leaves only 4 + 5.
The 9+ cage at row 5, column 2 (2 cells) could be 2 + 7, 3 + 6 or 4 + 5 — the grid leaves only 3 + 6.
The 7+ cage at row 1, column 4 (3 cells) could be 1 + 1 + 5, 1 + 2 + 4, 1 + 3 + 3 or 2 + 2 + 3 — the grid leaves only 2 + 2 + 3.
The 10+ cage at row 4, column 6 (3 cells) could be 1 + 2 + 7, 1 + 3 + 6, 1 + 4 + 5 or 2 + 3 + 5 — the grid leaves only 1 + 2 + 7.
The 3− cage at row 3, column 1 (2 cells) could be 4 − 1, 5 − 2, 6 − 3 or 7 − 4 — the grid leaves only 6 − 3.
The 12+ cage at row 5, column 4 (3 cells) could be 1 + 4 + 7, 1 + 5 + 6, 2 + 3 + 7, 2 + 4 + 6 or 3 + 4 + 5 — the grid leaves only 1 + 4 + 7.
The 1− cage at row 1, column 7 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 7 − 6.
The 1− cage at row 4, column 5 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 7 − 6.
The 1− cage at row 6, column 5 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 3 − 2.
The 12+ cage at row 2, column 5 (3 cells) allows 7 combinations, from 1 + 4 + 7 to 3 + 4 + 5 — too many to start from; the cells around it settle it, as 1 + 5 + 6.
The moments that matter
Most of a solve is crossing candidates off a line until one is left. These are the steps where this grid actually turns:
Step 1 of 44. Work the 100× cage: with what the board already holds, only 5 can sit in row 6, column 7 and still hit the target.
On its own that cage allows only 4 × 5 × 5.
Step 6 of 44. Somewhere in this line the 5 must go — and row 1, column 2 is the only cell that can still take it.
Scanning a line for where a digit can still go — rather than what a cell can still hold — is what finds this one.
Step 33 of 44. Work the 24× cage: with what the board already holds, only 3 can sit in row 4, column 7 and still hit the target.
On its own that cage could be 1 × 4 × 6, 2 × 2 × 6 or 2 × 3 × 4; the digits already placed around it leave one.
How this grid gives way
Of the 44 cells left to fill after the 5 printed ones, 21 by a cage’s arithmetic leaving only one value that fits; 21 by crossing off what a cell’s row and column already hold until one digit was left; and 2 by finding the one place left in a line where a digit could still go. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.
The full solution
Show all 44 steps
Work the 100× cage: with what the board already holds, only 5 can sit in row 6, column 7 and still hit the target.
Work the 100× cage: with what the board already holds, only 5 can sit in row 7, column 6 and still hit the target.
Work the 100× cage: with what the board already holds, only 4 can sit in row 7, column 7 and still hit the target.
Work the 5− cage: with what the board already holds, only 1 can sit in row 7, column 2 and still hit the target.
Work the 5− cage: with what the board already holds, only 6 can sit in row 7, column 3 and still hit the target.
Somewhere in this line the 5 must go — and row 1, column 2 is the only cell that can still take it.
Work the 35× cage: with what the board already holds, only 7 can sit in row 1, column 1 and still hit the target.
Somewhere in this line the 4 must go — and row 2, column 2 is the only cell that can still take it.
Work the 5+ cage: with what the board already holds, only 1 can sit in row 2, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 3 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 2, column 4 has exactly one candidate left: 3.
Work the 7+ cage: with what the board already holds, only 2 can sit in row 1, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 6 has exactly one candidate left: 6.
Cross off what the row and column already rule out, and row 2, column 7 has exactly one candidate left: 7.
Work the 1− cage: with what the board already holds, only 6 can sit in row 1, column 7 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 5 has exactly one candidate left: 5.
Cross off what the row and column already rule out, and row 7, column 4 has exactly one candidate left: 7.
Cross off what the row and column already rule out, and row 5, column 4 has exactly one candidate left: 4.
Work the 12+ cage: with what the board already holds, only 1 can sit in row 6, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 4 has exactly one candidate left: 6.
Work the 12+ cage: with what the board already holds, only 1 can sit in row 3, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 5 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 1, column 5 has exactly one candidate left: 4.
Work the 72× cage: with what the board already holds, only 3 can sit in row 1, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 5 has exactly one candidate left: 2.
Work the 3− cage: with what the board already holds, only 3 can sit in row 3, column 1 and still hit the target.
Work the 3− cage: with what the board already holds, only 6 can sit in row 4, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 7 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 3, column 2 has exactly one candidate left: 7.
Work the 5− cage: with what the board already holds, only 2 can sit in row 4, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 3 has exactly one candidate left: 5.
Cross off what the row and column already rule out, and row 3, column 6 has exactly one candidate left: 4.
Work the 24× cage: with what the board already holds, only 3 can sit in row 4, column 7 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 5 has exactly one candidate left: 7.
Work the 1− cage: with what the board already holds, only 6 can sit in row 5, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 3 has exactly one candidate left: 4.
Work the 140× cage: with what the board already holds, only 7 can sit in row 5, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 6 has exactly one candidate left: 1.
Cross off what the row and column already rule out, and row 5, column 1 has exactly one candidate left: 5.
Work the 9+ cage: with what the board already holds, only 4 can sit in row 6, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 2 has exactly one candidate left: 3.
Work the 9+ cage: with what the board already holds, only 6 can sit in row 6, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 6 has exactly one candidate left: 2.
Work the 10+ cage: with what the board already holds, only 7 can sit in row 6, column 6 and still hit the target.