Fill every row and every column with the digits 1 to 7, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 10 addition cages, 2 subtraction cages, 5 multiplication cages and 2 division cages.
4 cells are printed for you: a 5 at row 2, column 5; a 5 at row 4, column 6; a 7 at row 7, column 1; and a 6 at row 7, column 2. Fill those in first, then let each one rule its digit out of its row and column.
3 cages allow a single combination of digits — the safest openings this grid offers: the 35× cage at row 1, column 4 (1 × 5 × 7); the 13+ cage at row 1, column 6 (6 + 7); the 7÷ cage at row 6, column 2 (7 ÷ 1).
Cage by cage
What each cage’s arithmetic allows on its own, before the rows and columns have a say — the most constrained first, which is the order worth looking at them in. Digits may repeat inside a cage only where the cells share no row or column.
The 35× cage at row 1, column 4 (3 cells) can only be 1 × 5 × 7.
The 13+ cage at row 1, column 6 (2 cells) can only be 6 + 7.
The 7÷ cage at row 6, column 2 (2 cells) can only be 7 ÷ 1.
The 60× cage at row 2, column 2 (3 cells) could be 2 × 5 × 6 or 3 × 4 × 5 — the grid leaves only 3 × 4 × 5.
The 48× cage at row 3, column 4 (3 cells) could be 2 × 4 × 6 or 3 × 4 × 4 — the grid leaves only 2 × 4 × 6.
The 16+ cage at row 3, column 5 (3 cells) could be 3 + 6 + 7 or 4 + 5 + 7 — the grid leaves only 3 + 6 + 7.
The 12× cage at row 1, column 3 (2 cells) could be 2 × 6 or 3 × 4 — the grid leaves only 3 × 4.
The 12× cage at row 7, column 5 (2 cells) could be 2 × 6 or 3 × 4 — the grid leaves only 3 × 4.
The 8+ cage at row 2, column 6 (2 cells) could be 1 + 7, 2 + 6 or 3 + 5 — the grid leaves only 2 + 6.
The 9+ cage at row 3, column 1 (2 cells) could be 2 + 7, 3 + 6 or 4 + 5 — the grid leaves only 3 + 6.
The 8+ cage at row 3, column 6 (2 cells) could be 1 + 7, 2 + 6 or 3 + 5 — the grid leaves only 1 + 7.
The 2÷ cage at row 4, column 7 (2 cells) could be 2 ÷ 1, 4 ÷ 2 or 6 ÷ 3 — the grid leaves only 4 ÷ 2.
The 7+ cage at row 5, column 1 (2 cells) could be 1 + 6, 2 + 5 or 3 + 4 — the grid leaves only 2 + 5.
The 9+ cage at row 5, column 4 (2 cells) could be 2 + 7, 3 + 6 or 4 + 5 — the grid leaves only 3 + 6.
The 7+ cage at row 1, column 1 (3 cells) could be 1 + 1 + 5, 1 + 2 + 4, 1 + 3 + 3 or 2 + 2 + 3 — the grid leaves only 1 + 2 + 4.
The 7+ cage at row 5, column 6 (3 cells) could be 1 + 1 + 5, 1 + 2 + 4, 1 + 3 + 3 or 2 + 2 + 3 — the grid leaves only 1 + 2 + 4.
The 2− cage at row 6, column 7 (2 cells) could be 3 − 1, 4 − 2, 5 − 3, 6 − 4 or 7 − 5 — the grid leaves only 5 − 3.
The 1− cage at row 7, column 3 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 2 − 1.
The 13+ cage at row 4, column 2 (3 cells) allows 8 combinations, from 1 + 5 + 7 to 4 + 4 + 5 — too many to start from; the cells around it settle it, as 1 + 5 + 7.
The moments that matter
Most of a solve is crossing candidates off a line until one is left. These are the steps where this grid actually turns:
Step 1 of 45. Work the 35× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target.
On its own that cage allows only 1 × 5 × 7.
Step 2 of 45. Somewhere in this line the 2 must go — and row 6, column 5 is the only cell that can still take it.
Scanning a line for where a digit can still go — rather than what a cell can still hold — is what finds this one.
Step 34 of 45. Work the 9+ cage: with what the board already holds, only 6 can sit in row 6, column 4 and still hit the target.
On its own that cage could be 2 + 7, 3 + 6 or 4 + 5; the digits already placed around it leave one.
How this grid gives way
Of the 45 cells left to fill after the 4 printed ones, 20 by a cage’s arithmetic leaving only one value that fits; 19 by crossing off what a cell’s row and column already hold until one digit was left; and 6 by finding the one place left in a line where a digit could still go. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.
The full solution
Show all 45 steps
Work the 35× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target.
Somewhere in this line the 2 must go — and row 6, column 5 is the only cell that can still take it.
Somewhere in this line the 1 must go — and row 1, column 5 is the only cell that can still take it.
Work the 35× cage: with what the board already holds, only 7 can sit in row 2, column 4 and still hit the target.
Somewhere in this line the 1 must go — and row 2, column 1 is the only cell that can still take it.
Somewhere in this line the 3 must go — and row 1, column 3 is the only cell that can still take it.
Work the 12× cage: with what the board already holds, only 4 can sit in row 2, column 3 and still hit the target.
Somewhere in this line the 3 must go — and row 2, column 2 is the only cell that can still take it.
Cross off what the row and column already rule out, and row 3, column 2 has exactly one candidate left: 4.
Work the 60× cage: with what the board already holds, only 5 can sit in row 3, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 2 has exactly one candidate left: 2.
Work the 7+ cage: with what the board already holds, only 4 can sit in row 1, column 1 and still hit the target.
Work the 48× cage: with what the board already holds, only 4 can sit in row 4, column 4 and still hit the target.
Work the 7+ cage: with what the board already holds, only 2 can sit in row 5, column 1 and still hit the target.
Work the 7+ cage: with what the board already holds, only 5 can sit in row 6, column 1 and still hit the target.
Work the 13+ cage: with what the board already holds, only 5 can sit in row 5, column 2 and still hit the target.
Somewhere in this line the 2 must go — and row 3, column 4 is the only cell that can still take it.
Work the 48× cage: with what the board already holds, only 6 can sit in row 4, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 1 has exactly one candidate left: 3.
Work the 9+ cage: with what the board already holds, only 6 can sit in row 3, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 5 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 4, column 2 has exactly one candidate left: 1.
Work the 13+ cage: with what the board already holds, only 7 can sit in row 5, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 7 has exactly one candidate left: 6.
Work the 8+ cage: with what the board already holds, only 2 can sit in row 2, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 7 has exactly one candidate left: 7.
Work the 13+ cage: with what the board already holds, only 6 can sit in row 1, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 6 has exactly one candidate left: 7.
Work the 8+ cage: with what the board already holds, only 1 can sit in row 3, column 7 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 5 has exactly one candidate left: 7.
Work the 16+ cage: with what the board already holds, only 6 can sit in row 5, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 7 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 5, column 4 has exactly one candidate left: 3.
Work the 9+ cage: with what the board already holds, only 6 can sit in row 6, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 6 has exactly one candidate left: 1.
Work the 7+ cage: with what the board already holds, only 4 can sit in row 6, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 7 has exactly one candidate left: 4.
Cross off what the row and column already rule out, and row 6, column 2 has exactly one candidate left: 7.
Work the 7÷ cage: with what the board already holds, only 1 can sit in row 6, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 7 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 7, column 3 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 7, column 4 has exactly one candidate left: 1.
Cross off what the row and column already rule out, and row 7, column 5 has exactly one candidate left: 4.
Work the 12× cage: with what the board already holds, only 3 can sit in row 7, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 7 has exactly one candidate left: 5.