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Daily calcudoku

Saturday, 17 October 2026 · 7×7 Medium

The puzzle

The 7×7 grid for 17 October 2026, unsolved 7+ 12× 35× 13+ 60× 8+ 9+ 48× 16+ 8+ 13+ 2÷ 7+ 9+ 7+ 7÷ 2− 1− 12× 5 5 7 6

Fill every row and every column with the digits 1 to 7, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 10 addition cages, 2 subtraction cages, 5 multiplication cages and 2 division cages.

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Where to start

4 cells are printed for you: a 5 at row 2, column 5; a 5 at row 4, column 6; a 7 at row 7, column 1; and a 6 at row 7, column 2. Fill those in first, then let each one rule its digit out of its row and column.

3 cages allow a single combination of digits — the safest openings this grid offers: the 35× cage at row 1, column 4 (1 × 5 × 7); the 13+ cage at row 1, column 6 (6 + 7); the 7÷ cage at row 6, column 2 (7 ÷ 1).

Cage by cage

What each cage’s arithmetic allows on its own, before the rows and columns have a say — the most constrained first, which is the order worth looking at them in. Digits may repeat inside a cage only where the cells share no row or column.

The moments that matter

Most of a solve is crossing candidates off a line until one is left. These are the steps where this grid actually turns:

  1. Step 1 of 45. Work the 35× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target. On its own that cage allows only 1 × 5 × 7.
  2. Step 2 of 45. Somewhere in this line the 2 must go — and row 6, column 5 is the only cell that can still take it. Scanning a line for where a digit can still go — rather than what a cell can still hold — is what finds this one.
  3. Step 34 of 45. Work the 9+ cage: with what the board already holds, only 6 can sit in row 6, column 4 and still hit the target. On its own that cage could be 2 + 7, 3 + 6 or 4 + 5; the digits already placed around it leave one.

How this grid gives way

Of the 45 cells left to fill after the 4 printed ones, 20 by a cage’s arithmetic leaving only one value that fits; 19 by crossing off what a cell’s row and column already hold until one digit was left; and 6 by finding the one place left in a line where a digit could still go. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.

The full solution

Show all 45 steps
  1. Work the 35× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target.
  2. Somewhere in this line the 2 must go — and row 6, column 5 is the only cell that can still take it.
  3. Somewhere in this line the 1 must go — and row 1, column 5 is the only cell that can still take it.
  4. Work the 35× cage: with what the board already holds, only 7 can sit in row 2, column 4 and still hit the target.
  5. Somewhere in this line the 1 must go — and row 2, column 1 is the only cell that can still take it.
  6. Somewhere in this line the 3 must go — and row 1, column 3 is the only cell that can still take it.
  7. Work the 12× cage: with what the board already holds, only 4 can sit in row 2, column 3 and still hit the target.
  8. Somewhere in this line the 3 must go — and row 2, column 2 is the only cell that can still take it.
  9. Cross off what the row and column already rule out, and row 3, column 2 has exactly one candidate left: 4.
  10. Work the 60× cage: with what the board already holds, only 5 can sit in row 3, column 3 and still hit the target.
  11. Cross off what the row and column already rule out, and row 1, column 2 has exactly one candidate left: 2.
  12. Work the 7+ cage: with what the board already holds, only 4 can sit in row 1, column 1 and still hit the target.
  13. Work the 48× cage: with what the board already holds, only 4 can sit in row 4, column 4 and still hit the target.
  14. Work the 7+ cage: with what the board already holds, only 2 can sit in row 5, column 1 and still hit the target.
  15. Work the 7+ cage: with what the board already holds, only 5 can sit in row 6, column 1 and still hit the target.
  16. Work the 13+ cage: with what the board already holds, only 5 can sit in row 5, column 2 and still hit the target.
  17. Somewhere in this line the 2 must go — and row 3, column 4 is the only cell that can still take it.
  18. Work the 48× cage: with what the board already holds, only 6 can sit in row 4, column 3 and still hit the target.
  19. Cross off what the row and column already rule out, and row 4, column 1 has exactly one candidate left: 3.
  20. Work the 9+ cage: with what the board already holds, only 6 can sit in row 3, column 1 and still hit the target.
  21. Cross off what the row and column already rule out, and row 3, column 5 has exactly one candidate left: 3.
  22. Cross off what the row and column already rule out, and row 4, column 2 has exactly one candidate left: 1.
  23. Work the 13+ cage: with what the board already holds, only 7 can sit in row 5, column 3 and still hit the target.
  24. Cross off what the row and column already rule out, and row 2, column 7 has exactly one candidate left: 6.
  25. Work the 8+ cage: with what the board already holds, only 2 can sit in row 2, column 6 and still hit the target.
  26. Cross off what the row and column already rule out, and row 1, column 7 has exactly one candidate left: 7.
  27. Work the 13+ cage: with what the board already holds, only 6 can sit in row 1, column 6 and still hit the target.
  28. Cross off what the row and column already rule out, and row 3, column 6 has exactly one candidate left: 7.
  29. Work the 8+ cage: with what the board already holds, only 1 can sit in row 3, column 7 and still hit the target.
  30. Cross off what the row and column already rule out, and row 4, column 5 has exactly one candidate left: 7.
  31. Work the 16+ cage: with what the board already holds, only 6 can sit in row 5, column 5 and still hit the target.
  32. Cross off what the row and column already rule out, and row 4, column 7 has exactly one candidate left: 2.
  33. Cross off what the row and column already rule out, and row 5, column 4 has exactly one candidate left: 3.
  34. Work the 9+ cage: with what the board already holds, only 6 can sit in row 6, column 4 and still hit the target.
  35. Cross off what the row and column already rule out, and row 5, column 6 has exactly one candidate left: 1.
  36. Work the 7+ cage: with what the board already holds, only 4 can sit in row 6, column 6 and still hit the target.
  37. Cross off what the row and column already rule out, and row 5, column 7 has exactly one candidate left: 4.
  38. Cross off what the row and column already rule out, and row 6, column 2 has exactly one candidate left: 7.
  39. Work the 7÷ cage: with what the board already holds, only 1 can sit in row 6, column 3 and still hit the target.
  40. Cross off what the row and column already rule out, and row 6, column 7 has exactly one candidate left: 3.
  41. Cross off what the row and column already rule out, and row 7, column 3 has exactly one candidate left: 2.
  42. Cross off what the row and column already rule out, and row 7, column 4 has exactly one candidate left: 1.
  43. Cross off what the row and column already rule out, and row 7, column 5 has exactly one candidate left: 4.
  44. Work the 12× cage: with what the board already holds, only 3 can sit in row 7, column 6 and still hit the target.
  45. Cross off what the row and column already rule out, and row 7, column 7 has exactly one candidate left: 5.
Show the finished grid
The solved grid for 17 October 2026 7+ 12× 35× 13+ 60× 8+ 9+ 48× 16+ 8+ 13+ 2÷ 7+ 9+ 7+ 7÷ 2− 1− 12× 4 2 3 5 1 6 7 1 3 4 7 5 2 6 6 4 5 2 3 7 1 3 1 6 4 7 5 2 2 5 7 3 6 1 4 5 7 1 6 2 4 3 7 6 2 1 4 3 5