Fill every row and every column with the digits 1 to 7, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 6 addition cages, 5 subtraction cages and 7 multiplication cages.
9 cells are printed for you: a 2 at row 2, column 2; a 7 at row 2, column 3; a 6 at row 3, column 2; a 2 at row 3, column 4; a 7 at row 3, column 5; a 4 at row 3, column 6; a 7 at row 5, column 1; a 4 at row 5, column 3; and a 7 at row 7, column 2. Fill those in first, then let each one rule its digit out of its row and column.
6 cages allow a single combination of digits — the safest openings this grid offers: the 126× cage at row 6, column 4 (3 × 6 × 7); the 35× cage at row 1, column 6 (5 × 7); the 3× cage at row 2, column 1 (1 × 3); the 4+ cage at row 3, column 3 (1 + 3), among others.
Cage by cage
What each cage’s arithmetic allows on its own, before the rows and columns have a say — the most constrained first, which is the order worth looking at them in. Digits may repeat inside a cage only where the cells share no row or column.
The 126× cage at row 6, column 4 (3 cells) can only be 3 × 6 × 7.
The 35× cage at row 1, column 6 (2 cells) can only be 5 × 7.
The 3× cage at row 2, column 1 (2 cells) can only be 1 × 3.
The 4+ cage at row 3, column 3 (2 cells) can only be 1 + 3.
The 35× cage at row 3, column 7 (2 cells) can only be 5 × 7.
The 20× cage at row 6, column 1 (2 cells) can only be 4 × 5.
The 30× cage at row 6, column 3 (3 cells) could be 1 × 5 × 6 or 2 × 3 × 5 — the grid leaves only 2 × 3 × 5.
The 6× cage at row 2, column 4 (2 cells) could be 1 × 6 or 2 × 3 — the grid leaves only 1 × 6.
The 11+ cage at row 4, column 1 (2 cells) could be 4 + 7 or 5 + 6 — the grid leaves only 5 + 6.
The 9+ cage at row 1, column 1 (3 cells) could be 1 + 2 + 6, 1 + 3 + 5 or 2 + 3 + 4 — the grid leaves only 1 + 2 + 6.
The 7+ cage at row 5, column 2 (2 cells) could be 1 + 6, 2 + 5 or 3 + 4 — the grid leaves only 3 + 4.
The 4− cage at row 5, column 6 (2 cells) could be 5 − 1, 6 − 2 or 7 − 3 — the grid leaves only 6 − 2.
The 7+ cage at row 5, column 7 (2 cells) could be 1 + 6, 2 + 5 or 3 + 4 — the grid leaves only 1 + 6.
The 3− cage at row 4, column 4 (2 cells) could be 4 − 1, 5 − 2, 6 − 3 or 7 − 4 — the grid leaves only 4 − 1.
The 1− cage at row 1, column 4 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 5 − 4.
The 1− cage at row 1, column 7 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 4 − 3.
The 1− cage at row 7, column 6 (2 cells) could be 2 − 1, 3 − 2, 4 − 3, 5 − 4, 6 − 5 or 7 − 6 — the grid leaves only 2 − 1.
The 10+ cage at row 4, column 5 (3 cells) allows 7 combinations, from 1 + 2 + 7 to 3 + 3 + 4 — too many to start from; the cells around it settle it, as 2 + 3 + 5.
The moments that matter
Most of a solve is crossing candidates off a line until one is left. These are the steps where this grid actually turns:
Step 2 of 40. Work the 35× cage: with what the board already holds, only 5 can sit in row 2, column 6 and still hit the target.
On its own that cage allows only 5 × 7.
Step 13 of 40. Somewhere in this line the 2 must go — and row 1, column 1 is the only cell that can still take it.
Scanning a line for where a digit can still go — rather than what a cell can still hold — is what finds this one.
Step 27 of 40. Work the 6× cage: with what the board already holds, only 6 can sit in row 2, column 4 and still hit the target.
On its own that cage could be 1 × 6 or 2 × 3; the digits already placed around it leave one.
How this grid gives way
Of the 40 cells left to fill after the 9 printed ones, 20 by a cage’s arithmetic leaving only one value that fits; 17 by crossing off what a cell’s row and column already hold until one digit was left; and 3 by finding the one place left in a line where a digit could still go. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.
The full solution
Show all 40 steps
Cross off what the row and column already rule out, and row 1, column 6 has exactly one candidate left: 7.
Work the 35× cage: with what the board already holds, only 5 can sit in row 2, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 7 has exactly one candidate left: 5.
Work the 35× cage: with what the board already holds, only 7 can sit in row 4, column 7 and still hit the target.
Work the 11+ cage: with what the board already holds, only 6 can sit in row 4, column 1 and still hit the target.
Work the 11+ cage: with what the board already holds, only 5 can sit in row 4, column 2 and still hit the target.
Work the 7+ cage: with what the board already holds, only 3 can sit in row 5, column 2 and still hit the target.
Work the 7+ cage: with what the board already holds, only 4 can sit in row 6, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 2 has exactly one candidate left: 1.
Cross off what the row and column already rule out, and row 6, column 1 has exactly one candidate left: 5.
Work the 20× cage: with what the board already holds, only 4 can sit in row 7, column 1 and still hit the target.
Work the 126× cage: with what the board already holds, only 7 can sit in row 6, column 4 and still hit the target.
Somewhere in this line the 2 must go — and row 1, column 1 is the only cell that can still take it.
Work the 9+ cage: with what the board already holds, only 6 can sit in row 1, column 3 and still hit the target.
Somewhere in this line the 4 must go — and row 1, column 5 is the only cell that can still take it.
Cross off what the row and column already rule out, and row 1, column 7 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 1, column 4 has exactly one candidate left: 5.
Cross off what the row and column already rule out, and row 2, column 7 has exactly one candidate left: 4.
Work the 30× cage: with what the board already holds, only 5 can sit in row 7, column 3 and still hit the target.
Somewhere in this line the 3 must go — and row 2, column 1 is the only cell that can still take it.
Work the 3× cage: with what the board already holds, only 1 can sit in row 3, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 3 has exactly one candidate left: 3.
Work the 4+ cage: with what the board already holds, only 1 can sit in row 4, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 3 has exactly one candidate left: 2.
Work the 30× cage: with what the board already holds, only 3 can sit in row 7, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 5 has exactly one candidate left: 1.
Work the 6× cage: with what the board already holds, only 6 can sit in row 2, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 4 has exactly one candidate left: 4.
Cross off what the row and column already rule out, and row 5, column 4 has exactly one candidate left: 1.
Cross off what the row and column already rule out, and row 6, column 5 has exactly one candidate left: 3.
Work the 126× cage: with what the board already holds, only 6 can sit in row 7, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 5 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 4, column 6 has exactly one candidate left: 3.
Work the 10+ cage: with what the board already holds, only 5 can sit in row 5, column 5 and still hit the target.
Work the 4− cage: with what the board already holds, only 2 can sit in row 5, column 6 and still hit the target.
Work the 4− cage: with what the board already holds, only 6 can sit in row 6, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 7 has exactly one candidate left: 6.
Work the 7+ cage: with what the board already holds, only 1 can sit in row 6, column 7 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 6 has exactly one candidate left: 1.
Work the 1− cage: with what the board already holds, only 2 can sit in row 7, column 7 and still hit the target.