Fill every row and every column with the digits 1 to 7, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 8 addition cages, 4 subtraction cages, 4 multiplication cages and 1 division cage.
6 cells are printed for you: a 7 at row 1, column 7; a 6 at row 3, column 6; a 6 at row 4, column 7; a 4 at row 5, column 4; a 2 at row 5, column 7; and a 7 at row 6, column 4. Fill those in first, then let each one rule its digit out of its row and column.
The first moves a careful solver finds:
Work the 180× cage: with what the board already holds, only 6 can sit in row 1, column 3 and still hit the target.
Work the 180× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target.
Work the 180× cage: with what the board already holds, only 6 can sit in row 2, column 4 and still hit the target.
How this grid gives way
Of the 43 cells left to fill after the 6 printed ones, 20 by a cage’s arithmetic leaving only one value that fits; 19 by crossing off what a cell’s row and column already hold until one digit was left; and 4 by finding the one place left in a line where a digit could still go. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.
The full solution
Show all 43 steps
Work the 180× cage: with what the board already holds, only 6 can sit in row 1, column 3 and still hit the target.
Work the 180× cage: with what the board already holds, only 5 can sit in row 1, column 4 and still hit the target.
Work the 180× cage: with what the board already holds, only 6 can sit in row 2, column 4 and still hit the target.
Work the 14× cage: with what the board already holds, only 7 can sit in row 2, column 6 and still hit the target.
Somewhere in this line the 7 must go — and row 5, column 3 is the only cell that can still take it.
Cross off what the row and column already rule out, and row 5, column 2 has exactly one candidate left: 1.
Work the 10+ cage: with what the board already holds, only 2 can sit in row 4, column 3 and still hit the target.
Work the 1− cage: with what the board already holds, only 4 can sit in row 4, column 6 and still hit the target.
Work the 1− cage: with what the board already holds, only 6 can sit in row 5, column 5 and still hit the target.
Work the 90× cage: with what the board already holds, only 6 can sit in row 6, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 1 has exactly one candidate left: 7.
Work the 13+ cage: with what the board already holds, only 6 can sit in row 7, column 2 and still hit the target.
Somewhere in this line the 1 must go — and row 4, column 4 is the only cell that can still take it.
Somewhere in this line the 2 must go — and row 6, column 2 is the only cell that can still take it.
Somewhere in this line the 3 must go — and row 2, column 3 is the only cell that can still take it.
Cross off what the row and column already rule out, and row 1, column 2 has exactly one candidate left: 3.
Work the 10+ cage: with what the board already holds, only 4 can sit in row 2, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 7 has exactly one candidate left: 1.
Work the 4÷ cage: with what the board already holds, only 4 can sit in row 3, column 7 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 7 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 5, column 6 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 5, column 1 has exactly one candidate left: 5.
Work the 90× cage: with what the board already holds, only 3 can sit in row 4, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 1 has exactly one candidate left: 2.
Work the 2− cage: with what the board already holds, only 4 can sit in row 1, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 5 has exactly one candidate left: 5.
Cross off what the row and column already rule out, and row 3, column 1 has exactly one candidate left: 1.
Cross off what the row and column already rule out, and row 3, column 3 has exactly one candidate left: 5.
Work the 8+ cage: with what the board already holds, only 2 can sit in row 3, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 2 has exactly one candidate left: 7.
Work the 13+ cage: with what the board already holds, only 5 can sit in row 4, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 5 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 4, column 5 has exactly one candidate left: 7.
Cross off what the row and column already rule out, and row 6, column 3 has exactly one candidate left: 1.
Work the 7+ cage: with what the board already holds, only 4 can sit in row 7, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 5 has exactly one candidate left: 4.
Work the 60× cage: with what the board already holds, only 5 can sit in row 6, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 4 has exactly one candidate left: 3.
Work the 5+ cage: with what the board already holds, only 2 can sit in row 7, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 5 has exactly one candidate left: 1.
Work the 14× cage: with what the board already holds, only 2 can sit in row 1, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 7, column 6 has exactly one candidate left: 1.
Work the 6+ cage: with what the board already holds, only 5 can sit in row 7, column 7 and still hit the target.