Fill every row and every column with the digits 1 to 6, each exactly once, so that the digits in every outlined cage combine to its target with its operation. This one has 5 addition cages, 3 subtraction cages, 3 multiplication cages and 1 division cage.
9 cells are printed for you: a 6 at row 3, column 1; a 2 at row 3, column 2; a 4 at row 3, column 4; a 3 at row 4, column 2; a 5 at row 4, column 3; a 5 at row 5, column 2; a 4 at row 5, column 3; a 6 at row 6, column 3; and a 2 at row 6, column 4. Fill those in first, then let each one rule its digit out of its row and column.
The first moves a careful solver finds:
Cross off what the row and column already rule out, and row 1, column 3 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 1, column 1 has exactly one candidate left: 4.
Work the 48× cage: with what the board already holds, only 6 can sit in row 1, column 2 and still hit the target.
How this grid gives way
Of the 27 cells left to fill after the 9 printed ones, 16 by crossing off what a cell’s row and column already hold until one digit was left; and 11 by a cage’s arithmetic leaving only one value that fits. No step needs a guess: every Cages daily is checked to have exactly one solution, reachable by reasoning alone.
The full solution
Show all 27 steps
Cross off what the row and column already rule out, and row 1, column 3 has exactly one candidate left: 2.
Cross off what the row and column already rule out, and row 1, column 1 has exactly one candidate left: 4.
Work the 48× cage: with what the board already holds, only 6 can sit in row 1, column 2 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 4 has exactly one candidate left: 5.
Work the 11+ cage: with what the board already holds, only 6 can sit in row 2, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 1, column 5 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 1, column 6 has exactly one candidate left: 1.
Work the 6+ cage: with what the board already holds, only 2 can sit in row 2, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 2 has exactly one candidate left: 4.
Cross off what the row and column already rule out, and row 3, column 3 has exactly one candidate left: 3.
Work the 4+ cage: with what the board already holds, only 1 can sit in row 2, column 3 and still hit the target.
Cross off what the row and column already rule out, and row 2, column 6 has exactly one candidate left: 3.
Cross off what the row and column already rule out, and row 2, column 1 has exactly one candidate left: 5.
Cross off what the row and column already rule out, and row 3, column 5 has exactly one candidate left: 1.
Work the 4÷ cage: with what the board already holds, only 4 can sit in row 4, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 3, column 6 has exactly one candidate left: 5.
Work the 14+ cage: with what the board already holds, only 6 can sit in row 4, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 1 has exactly one candidate left: 2.
Work the 2× cage: with what the board already holds, only 1 can sit in row 5, column 1 and still hit the target.
Cross off what the row and column already rule out, and row 4, column 4 has exactly one candidate left: 1.
Work the 3× cage: with what the board already holds, only 3 can sit in row 5, column 4 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 5 has exactly one candidate left: 6.
Work the 1− cage: with what the board already holds, only 5 can sit in row 6, column 5 and still hit the target.
Cross off what the row and column already rule out, and row 5, column 6 has exactly one candidate left: 2.
Work the 2− cage: with what the board already holds, only 4 can sit in row 6, column 6 and still hit the target.
Cross off what the row and column already rule out, and row 6, column 1 has exactly one candidate left: 3.
Work the 4+ cage: with what the board already holds, only 1 can sit in row 6, column 2 and still hit the target.